On the issue of being overworked
Jan. 19th, 2003 08:14 pm![[personal profile]](https://www.dreamwidth.org/img/silk/identity/user.png){kind=small}
tarigwaemirAd Mundo Exteriore,
I wasn't going to post anything at all, but I just had to complain. My professor just told me that the sources I cited for my paper are bogus. So now I have to dig through the HCHS library online journal subscriptions to find the ones that are definitive. How was I supposed to know what's definitive or not?! And he wants me to cite a book that I haven't even looked at yet! Oy vey...
I could of course always look at it later and cite it anyway...
Look at me, with my breaches of academic integrity. On the other hand, do I really care? ::thinks:: Probably not. I want to analyze my data, not make sure that the information which is commonly known to all the researchers in the field is properly cited for the sake of the silly Expo people.
In other news, I finished both the HUNS country profile for Luxembourg and edited my papers so that they actually have footnotes. They are still however half the length of those of my delegates. Did I mention that I also have two exams on Tuesday? ::sobs:: And one's in AP Physics, too! Oh dear. Screw the science fair, I'm going to go study rotational motion as soon as I find all these dratted sources.
Final omega squared equals initial omega squared plus two times alpha times angular displacement...
L.D., Lydia, kaydee, Nikolai? You have no legitimate reason to be complaining about regular Physics. For one, you don't have to deal with Greek letters that look like English letters, except they're not. ::sticks tongue out::
Let's see, for simple harmonic motion, the displacement from the equilibrium position is given by the formula of amplitude times the cosine of omega times time plus delta, where omega is the angular frequency and delta is the phase of motion.
Um...velocity equals omega times radius? Or was it omega equals velocity times radius? Wait, let's think about this. Arclength equals angle times radius, so divide both sides by time, and you get velocity equals omega times radius. Whew. I should remember how to derive that.
And in rolling motion...er...I forget about rolling motion.
::looks up from her frantic typing and realizes that people are snoring around her:: Oh, sorry. Ignore the above. Although it really is helpful, not to mention slightly therapeutic, to randomly start spouting formulas when you're panicking about AP Physics.
...Tari
Post-script: I need a panicked LJ icon.
I wasn't going to post anything at all, but I just had to complain. My professor just told me that the sources I cited for my paper are bogus. So now I have to dig through the HCHS library online journal subscriptions to find the ones that are definitive. How was I supposed to know what's definitive or not?! And he wants me to cite a book that I haven't even looked at yet! Oy vey...
I could of course always look at it later and cite it anyway...
Look at me, with my breaches of academic integrity. On the other hand, do I really care? ::thinks:: Probably not. I want to analyze my data, not make sure that the information which is commonly known to all the researchers in the field is properly cited for the sake of the silly Expo people.
In other news, I finished both the HUNS country profile for Luxembourg and edited my papers so that they actually have footnotes. They are still however half the length of those of my delegates. Did I mention that I also have two exams on Tuesday? ::sobs:: And one's in AP Physics, too! Oh dear. Screw the science fair, I'm going to go study rotational motion as soon as I find all these dratted sources.
Final omega squared equals initial omega squared plus two times alpha times angular displacement...
L.D., Lydia, kaydee, Nikolai? You have no legitimate reason to be complaining about regular Physics. For one, you don't have to deal with Greek letters that look like English letters, except they're not. ::sticks tongue out::
Let's see, for simple harmonic motion, the displacement from the equilibrium position is given by the formula of amplitude times the cosine of omega times time plus delta, where omega is the angular frequency and delta is the phase of motion.
Um...velocity equals omega times radius? Or was it omega equals velocity times radius? Wait, let's think about this. Arclength equals angle times radius, so divide both sides by time, and you get velocity equals omega times radius. Whew. I should remember how to derive that.
And in rolling motion...er...I forget about rolling motion.
::looks up from her frantic typing and realizes that people are snoring around her:: Oh, sorry. Ignore the above. Although it really is helpful, not to mention slightly therapeutic, to randomly start spouting formulas when you're panicking about AP Physics.
...Tari
Post-script: I need a panicked LJ icon.
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(no subject)
Date: 2003-01-20 07:58 pm (UTC)::runs off to die::
Re:
Date: 2003-01-22 10:09 am (UTC)...Tari